Drag the tiles to the boxes to form correct pairs.Match the pairs of equivalent expressions.

Answer:The following pairs/results are matched:[tex]5\left(2t+1\right)+\left(-7t+28\right)[/tex] = [tex]3t+33[/tex] [tex]3\left(3t-4\right)-\left(2t+10\right)[/tex] = [tex]7t-22[/tex][tex]\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)[/tex] = [tex]\frac{16t}{3}-\frac{23}{5}[/tex][tex]\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)[/tex] = [tex]-\frac{11}{4}t+36[/tex]Step-by-step explanation:Lets solve all the expressions to match the results.[tex]5\left(2t+1\right)+\left(-7t+28\right)[/tex]Solving the expression[tex]5\left(2t+1\right)+\left(-7t+28\right)[/tex][tex]\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a[/tex][tex]5\left(2t+1\right)-7t+28[/tex][tex]10t+5-7t+28[/tex][tex]3t+33[/tex]Therefore, [tex]5\left(2t+1\right)+\left(-7t+28\right)[/tex] = [tex]3t+33[/tex][tex]3\left(3t-4\right)-\left(2t+10\right)[/tex]Solving the expression[tex]3\left(3t-4\right)-\left(2t+10\right)[/tex][tex]9t-12-\left(2t+10\right)[/tex][tex]9t-12-2t-10[/tex][tex]7t-22[/tex]Therefore, [tex]3\left(3t-4\right)-\left(2t+10\right)[/tex] = [tex]7t-22[/tex][tex]\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)[/tex]Solving the expression[tex]\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)[/tex][tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex][tex]4t-\frac{8}{5}-\left(3-\frac{4}{3}t\right)[/tex][tex]4t-\frac{8}{5}-\left(-\frac{4t}{3}+3\right)[/tex][tex]4t-\frac{8}{5}-3+\frac{4t}{3}[/tex]As [tex]-3-\frac{8}{5}:\quad -\frac{23}{5}[/tex]    and  [tex]\frac{4t}{3}+4t:\quad \frac{16t}{3}[/tex]So, [tex]4t-\frac{8}{5}-3+\frac{4t}{3}[/tex] will become [tex]\frac{16t}{3}-\frac{23}{5}[/tex]Therefore, [tex]\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)[/tex] = [tex]\frac{16t}{3}-\frac{23}{5}[/tex][tex]\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)[/tex]Solving the expression[tex]\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)[/tex][tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex][tex]-\frac{9}{2}t+3+\frac{7}{4}t+33[/tex][tex]\mathrm{Group\:like\:terms}[/tex][tex]\frac{9}{2}t+\frac{7}{4}t+3+33[/tex][tex]\mathrm{Add\:similar\:elements:}\:-\frac{9}{2}t+\frac{7}{4}t=-\frac{11}{4}t[/tex][tex]-\frac{11}{4}t+3+33[/tex][tex]-\frac{11}{4}t+36[/tex]Therefore, [tex]\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)[/tex] = [tex]-\frac{11}{4}t+36[/tex]Thus, the following pairs/results are matched:[tex]5\left(2t+1\right)+\left(-7t+28\right)[/tex] = [tex]3t+33[/tex] [tex]3\left(3t-4\right)-\left(2t+10\right)[/tex] = [tex]7t-22[/tex][tex]\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)[/tex] = [tex]\frac{16t}{3}-\frac{23}{5}[/tex][tex]\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)[/tex] = [tex]-\frac{11}{4}t+36[/tex]Keywords: algebraic expressionLearn more about algebraic expression from brainly.com/question/11336599#learnwithBrainly